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RIBAUCOUR CURVE
Problem posed by Jean Bernoulli in 1716, solved by Taylor
in 1717; curve then studied by Ossian Bonnet in 1844 and Ribaucour in 1880.
Albert Ribaucour (1845-1893): French mathematician and engineer. See also this link. |
Second order differential equation: .
First order equation: . Cartesian equation: . Cartesian parametrization: , with . Algebraic curve for k odd integer. Curvilinear abscissa given by . Radius of curvature: . |
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For k a positive integer, we can take any value of t; the curve is closed when k is odd, periodic when k is even. |
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When k is positive and not an integer, take . |
Case k = -1/4, -1/2, -1 (catenary), -2 (parabola). |
When k negative, take ; the curve has a vertical asymptote when k> -1, and a parabolic branch otherwise. |
A Ribaucour curve is a curve for which any point M on the curve satisfies where I is the centre of curvature at M, N the intersection point between (MI) and a given line (D) (here: Ox) and k is a given constant. |
In other words, with Ox as the line (D), they are the curves such that the radius of curvature is proportional to the normal: Rc = – k N.
The Ribaucour curve of index k is also the locus of the pole of the sinusoidal spiral: rolling without slipping on (D), with .
Finally, it is the solution to the calculus of variations problem that consists in determining the curve for which the integral is extremal; this is why it is also the trajectory of a light ray in an inhomogeneous medium: see this page devoted to the Fermat principle.
Special case:
Index of the Ribaucour curve | Nature of this curve | Index
of the rolling sinusoidal spiral |
Nature of this spiral | figure | Integral for which the Ribaucour curve is an extremum | Interpretation |
k = –2 | parabola with directrix (D) | n = –1/3 | Tschirnhausen cubic, with tracing point at the focus |
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k = –1 | catenary with base (D) | n = –1/2 | parabola, with tracing point at the focus |
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curve joining A to B for which the area of the surface spanned by its rotation around (D) is minimal, such a surface is a catenoid. | |
k = –1/2 | see the last column | n = –2/3 | central negative pedal of the rectangular hyperbola |
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homogeneous massive wire joining A to B with minimal moment of inertia | |
k = 0 | point | n = –1 | line | .... | .... | |
k = 1/2 | rectangular Sturm roulette
or right lintearia |
n = –2 | rectangular hyperbola |
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? | |
k = 1 | circle centred on (D) | n infinite | .... | geodesic in the Poincaré half-plane | ||
k = 3/2 | n = 2 | lemniscate of Bernoulli | see the animation above | ? | ||
k = 2 | cycloid with cuspidal points on (D) | n = 1 | circle, with tracing point on the circle | brachistochrone curve | ||
k = 3 | sextic
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n = 1/2 | cardioid, with tracing point at the tip | ? | ||
k infinite | line | n = 0 | point | the line is the shortest path from a point to another... |
Nota: the equation shows that the Ribaucour curves, for k different from 0, can be defined by ; we can then consider that the curve of order 0 is the curve defined by which is none other than the catenary of equal strength.
Derivation of the equations from the 3 definitions above:
Proof starting with the definition by the property of the normals. | Proof starting with the rolling sinusoidal spiral | Proof starting with the calculus of variations problem |
The equation Rc = - k N can be written , hence and which give the equation with separated variables which leads to the solution given in the boxed paragraph above. | The equation of the roulette of the pole of the curve with polar equation is (1); but for the sinusoidal spiral: , and so (1) becomes , QED. | The Euler-Lagrange equation applied to the integral leads to the differential equation , which gives, with , the differential equation . Writing , we get the above parametrization. |
The Mannheim curve
of a Ribaucour curve is a Ribaucour curve with parameter k – 1.
The rotation of a Ribaucour curve around the Ox
axis gives a rotation
surface whose principal curvatures are
proportional
at each point.
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© Robert FERRÉOL 2017